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ale4655 [162]
3 years ago
11

Instead of having 1.5 times as many pink flowers as white flowers, molly has decided to plant a garden with twice as many pink f

lowers as white flowers per row
Mathematics
2 answers:
jekas [21]3 years ago
6 0

Answer:

To find the number of white flowers, use the constant of proportionality and the number of pink flowers per row. If Molly plants 4, 6, and 8 pink flowers in 3 rows, she has to plant 2, 3, and 4 white flowers in those rows, so there are twice as many pink flowers as white.

Step-by-step explanation:

This was the sample response on edge :)

harkovskaia [24]3 years ago
4 0

Answer:

Row 1 = 2 white flowers

Row 2 = 3 white flowers

Row 3 = 4 white flowers

Step-by-step explanation:

Instead of having 1.5 times as many pink flowers as white flowers, Molly has decided to plant a garden with twice as many pink flowers as white flowers per row. If she plants 3 rows, with 4, 6, and 8 pink flowers, how can you find the number of white flowers in each of those rows?

Let

White flowers = x

Pink flowers = 2x

Molly plants 3 rows with 4, 6 and 8 pink flowers

Number of white flowers in each row is

Row 1

Pink flowers = 4

2x = 4

Divide both sides by 2

x= 2

White flowers = 2 in row 1

Row 2

Pink flowers = 6

2x=6

Divide both sides by 2

x= 3

White flowers in row 2 = 3

Row 3

Pink flowers = 8

2x=8

Divide both sides by 2

x= 4

White flowers in row 3 = 4

Therefore, the number of white flowers in each rows are 2, 3 and 4 respectively

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If (x) = 3x - 5 and g(x) = x + 3, find (f - g)(x).
Temka [501]

Answer:

2x -8

Step-by-step explanation:

f (x) = 3x - 5

g(x) = x + 3,

(f - g)(x) = 3x - 5 - ( x+3)

Distribute the minus sign

            = 3x-5 -x-3

Combine like terms

           = 2x -8

8 0
3 years ago
Read 2 more answers
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
We test for a hypothesized difference between two population means: H0: μ1 = μ2. The population standard deviations are unknown
Lina20 [59]

Answer:

The degrees of freedom associated with the critical value is 25.

Step-by-step explanation:

The number of values in the final calculation of a statistic that are free to vary is referred to as the degrees of freedom. That is, it is the number of independent ways by which a dynamic system can move, without disrupting any constraint imposed on it.

The degrees of freedom for the t-distribution is obtained by substituting the values of n1​ and n2​ in the degrees of freedom formula.

Degrees of freedom, df = n1​+n2​−2

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Therefore, the degrees of freedom associated with the critical value is 25.

4 0
3 years ago
Two rectangles have a area of 81 square inches. Name two possible perimeters for the rectangles ​
jeka94

Answer:

3, 27 and 9,9

Step-by-step explanation:

3*27 = 81

9*9=81

Technically you could say 1 and 81 but those two answers fit the most.

3 0
3 years ago
Evaluate the following.
Dominik [7]

Answer:

5

Step-by-step explanation:

|8| - |14 - 11|

8 - 3

5

3 0
3 years ago
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