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3 years ago

Half the age of sally in algebraic expression

Mathematics

1 answer:

Olin [163]3 years ago

3 0

Answer:

sally= a1/2

Step-by-step explanation:

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shelly is going shopping at the mall to buy three pairs of shoes. she has a coupon for $2 off per pair of shoes after buying the

kvasek [131]

Okay, to start, we can multiply the $2 coupon by two because that is the amount of pairs she is going to by. So it would be $4 off. Now, if all of the shoes she purchased the same price, this is made a little easier. We can simply take $80 and $122 and add it by the $4 discount. Our new numbers would be $84 and $126. Now in order for this to work we would want all the numbers to be the same. We take $84 and divide it by three pairs, to get the values. For the least amount she can spend per pair is $28 and the most amount she can spend per pair is $42.

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3 years ago

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hodyreva [135]

Answer:

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Step-by-step explanation:

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2 years ago

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ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

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3 years ago

Simplify 2⁰+5¹+4³/7

Alekssandra [29.7K]

Your question has been heard loud and clear.

2^0= 1

5^1= 5

4^3=64

2^0+5^1+4^3/7= 1+5+64/7 = 6+64/7= 15.14

So , 2^0+5^1+4^3/7 = 15.14

Thank you

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3 years ago

Let f(x) = 6x-5 and g(x) = 2x-1. Find f • g

tankabanditka [31]

(6x-5) (2x-1) = 12x²-6x-10x+5 = 12x²-16x +5

3 0

3 years ago