Answer:
B, the second one.
Step-by-step explanation:
Take the equation, y=2x+1. 1 is the y-intercept, so that automatically eliminates some potential answer choices. Your slope is 2/1, so you would use rise over run to find the correct answer choice.
Answer:
Graph of the inequality 3y-2x>-18 is given below.
Step-by-step explanation:
We are given the inequality, 3y-2x>-18
Now, using the 'Zero Test', which states that,
After substituting the point (0,0) in the inequality, if the result is true, then the solution region is towards the origin. If the result is false, then the solution region is away from the origin'.
So, after substituting (0,0) in 3y-2x>-18, we get,
3\times 0-2\times 0>-18
i.e. 0 > -18, which is true.
Thus, the solution region is towards the origin.
Hence, the graph of the inequality 3y-2x>-18 is given below.
Answer:
<h2>7.4inches</h2>
Step-by-step explanation:
Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.
According to the rule;
![\frac{u}{sinU} = \frac{v}{sinV} = \frac{w}{sinW}\\\frac{u}{sinU} = \frac{w}{sinW}](https://tex.z-dn.net/?f=%5Cfrac%7Bu%7D%7BsinU%7D%20%3D%20%20%5Cfrac%7Bv%7D%7BsinV%7D%20%3D%20%5Cfrac%7Bw%7D%7BsinW%7D%5C%5C%5Cfrac%7Bu%7D%7BsinU%7D%20%3D%20%5Cfrac%7Bw%7D%7BsinW%7D)
Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;
![\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in](https://tex.z-dn.net/?f=%5Cfrac%7Bu%7D%7Bsin73%5E%7B0%7D%20%7D%20%3D%20%5Cfrac%7B3%7D%7Bsin23%5E%7B0%7D%20%7D%5C%5Cusin23%5E%7B0%7D%20%3D%203sin73%5E%7B0%7D%5C%5Cu%20%3D%20%5Cfrac%7B3sin73%5E%7B0%7D%20%7D%7Bsin23%5E%7B0%7D%20%7D%5C%5Cu%20%3D%20%5Cfrac%7B2.87%7D%7B0.39%7D%20%5C%5Cu%20%3D%207.358%5C%5Cu%20%3D%207.4in)
The length of u is 7.4inches to nearest 10th of an inch
Answer:
<h2>x = 745.5 ft</h2>
Step-by-step explanation:
Look at the picture.
Use sine:
![sine=\dfrac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=sine%3D%5Cdfrac%7Bopposite%7D%7Bhypotenuse%7D)
We have a measure of the angle and length of the opposite:
![\alpha=28^o,\ opposite=350\ ft](https://tex.z-dn.net/?f=%5Calpha%3D28%5Eo%2C%5C%20opposite%3D350%5C%20ft)
![\sin28^o\approx0.4695](https://tex.z-dn.net/?f=%5Csin28%5Eo%5Capprox0.4695)
Substitute:
![\dfrac{350}{x}=0.4695](https://tex.z-dn.net/?f=%5Cdfrac%7B350%7D%7Bx%7D%3D0.4695)
<em>cross multiply</em>
<em>divide both sides by 4695</em>
![x=\dfrac{3500000}{4695}\to x\approx745.5](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B3500000%7D%7B4695%7D%5Cto%20x%5Capprox745.5)
The next number in this pattern should be A)28