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Shalnov [3]
3 years ago
12

What is the average rate of change for this function for the interval from x=3 to x=5?

Mathematics
1 answer:
natima [27]3 years ago
3 0

Answer:

12

Step-by-step explanation:

The average rate of change of a function is the slope because

let g(x) = f'(x)

\frac{\int\limits^b_a {g(x)} \, dx }{b-a} = \frac{f(b)-f(a)}{b-a}

so we just need to calculate the slope of the function over the interval [3, 5]

\frac{f(5)-f(3)}{5-3} = \frac{37 - 13}{2} = \frac{24}{2} = 12

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Answer: 0.2 reduced as a fraction 1/5

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What is 689 divided by 24
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6 0
3 years ago
Read 2 more answers
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
Please answer 5,6,7. With explanation.
Anestetic [448]
First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them

12x^8/3x^3= 4x^8-3=4x^5

20^2x=20^x*20^x

m^5*m^-7=m^5-7=m^-2







8 0
3 years ago
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