F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
<span> 9.187 to the nearest tenth is 9.2
The 1 in 9.187 is in the tenths place and since the number after it is over 5, you round up. </span>
Differentiate using the exponential rule, which determines that
is
when a=3.

Therefore, the correct option is "E". You just have to remove the parentheses.

Answer:
you have to use the quadratic equation to find the zeros
Step-by-step explanation:
Answer:
0=2
There are no solutions
Step-by-step explanation: