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Daniel [21]
2 years ago
11

The equation y = – 5x +6 represents a

Mathematics
1 answer:
Alisiya [41]2 years ago
4 0

Answer:

y = 6   =  > x = 0 \\ y = 8 =  > x =  \frac{ - 2}{5}  \\ y = 100 =  > x =  \frac{ - 94}{5}

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Heyy!!
rosijanka [135]

<u>Answer:</u>

6^{10}

<u>Step-by-step explanation:</u>

We can use the following rule of surds to solve the problem:

\boxed{a^m \times a^n = a^{m + n}},

which means that when multiplying two numbers with the same bases, we can simply add their powers while keeping the base the same.

Applying this rule:

6^2 \times 6^8

⇒ 6^{2 + 8}

⇒ \bf 6^{10}

8 0
2 years ago
What is the value of B for the following triangular prism?
Vika [28.1K]

Answer:

56cm is not the answer for sure trust me

Step-by-step explanation:

I took the test so dont worry!

5 0
3 years ago
Read 2 more answers
Creating a One-Variable Equation to Model and Solve a Problem
guajiro [1.7K]

Answer:

The hourly fee for rototiller is $3 per hour.

Step-by-step explanation:

We are given the following in the equation:

The rental company  charged an initial fee of $43 with an additional fee per hour.

Let h represents the hourly fee.

The family paid $64 after renting the rototiller for 7 hours.

Thus, we can write the equation:

43 + 7h = 64

Solving the equation, we get,

43 + 7h = 64\\7h = 64-43\\7h = 21\\\Rightarrow h = 3

Thus, the hourly fee is $3 per hour.

Equation:

C(x) = 43 + 3x

where C(x) is the cost function and x is the number of hours rototiller is rented.

The hourly fee for rototiller is $3 per hour.

4 0
3 years ago
a gift box is 4 inches long 5 inches wide and 8 inches tall how much wrapping paper will it take to wrap thr box?
Natalka [10]
The answer is 160. U multiply all. PUT ME AS BEST
3 0
3 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
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