Subtract 9a^2-6a+59a 2 −6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 +3a+2510, a, squared, plus, 3, a, plus, 25
nasty-shy [4]
Answer:
The answer to your question is a² + 9a + 20
Step-by-step explanation:
10a² + 3a + 25 - (9a² - 6a + 5)
- Remove parentheses changing the sign of the second polynomial
10a² + 3a + 25 - 9a² + 6a - 5
- Group like terms
(10a² - 9a²) + (3a + 6a) + (25 - 5)
- Simplify and result
a² + 9a + 20
I don’t really know but I think one of them would be 150 adding 60 and 90
I would add, the weight of the backpack and the weight of the school books which is 28.36.
So Rico's backpack altogether weighs 28.36.
I'm pretty sure.
To do this you must plug in 1 and negative one for each x variable and each y. that solution is a point so the 1 must be tested for x and the -1 for y. do this and solve to find a and b so that it works in both equations!
Answer:
The Answer is: a^2 + 2ab + b^2
Step-by-step explanation:
Multiply the first factor resulting in the a squared, then the two inner factors resulting in ab + ab, finally the last term, resulting in b squared. Then combine terms:
(-a - b)(-a - b) =
a^2 + ab + ab + b^2 =
a^2 + 2ab + b^2
Hope this helps! Have an awesome day! :-)
