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3 years ago

HELLO!!! Please tell me that somebody knows how to do this. I don’t have a clue. Thank you so much❤️❤️❤️

Mathematics

1 answer:

xenn [34]3 years ago

3 0

For question one, the easiest way to start is with t=0, so, everything inside the sine function will equal 0, and sin(0) is 0, so that is our starting point. Then, consider the following:

sin(pi/2) = 1

sin(pi) = 0

sin(3pi/2) = -1

sin(2pi) = 0

(You need to know the unit circle)

Then, we see that t=4 is a solution since the 4 times a half is 2, exactly what we need for 2 (pi). Also because it goes around the unit circle.

Problem 2 you just need the period formula. It is [2pi / b] and b is the number in front of t. So we get (2pi / (2pi / 15)). Simplifying leads to 30pi over 2pi which is just 15. Thus the period is 15 units

Lastly, Problem 3 asks for the inverse of a period since the frequency is 1 over the period. Applying the method from the last problem:

2pi / 524pi which simplifies to 1 over 262 is the period.

Now flipping 1 over 262 gives the frequency, which is just 262 by itself

Hope this long explanation helped

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Find the length of AC on this triangle

Illusion [34]

Answer:

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan12° = $\frac{opposite}{adjacent}$ = $\frac{AC}{BC}$ = $\frac{AC}{44}$ ( multiply both sides by 44 )

44 × tan12° = AC , then

AC ≈ 9.35 ( to 2 dec. places )

4 0

3 years ago

If the probability of a student spending time reading is 0.10, the probability of spending time watching TV is 0.90 and the prob

joja [24]

Answer:

The probability is 0.97

Step-by-step explanation:

In this question, we are concerned with calculating the probability of a student spending time reading or watching TV.

To calculate this, we simply use a direct mathematical formula.

P( of spending time reading or watching tv) = P(of spending time reading) + P(spending time watching Tv) - P( of spending time watching Tv and reading)

From the question, we identify the probabilities as follows;

P(spending time reading) = 0.1

P(of spending time watching Tv) = 0.9

P(of spending time watching Tv and reading) = 0.03

Now, plugging these values, we have

P( of spending time reading or watching Tv) = 0.9 + 0.1 -0.03

= 1-0.03 = 0.97

6 0

3 years ago

For the equation -4y = 8x , what is the constant of variation?

Inga [223]

-4y = 8x

Divide both sides by -4

y = -2x

This is in the form of y = kx, where k is the constant of variation.
y = kx is the direct

That means, k = -2.

The constant of variation is B. -2.

7 0

3 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by $\nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}$

- (Gauss' theorem)Given a closed surface S, the following applies

$\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV$

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

$\nabla \cdot F = \frac{\partial}{\partial x}(x)+\frac{\partial}{\partial y}(2y)+ \frac{\partial}{\partial z}(5z) = 1+2+5 = 8$

Hence, by the Gauss theorem we have that

$\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}$

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

$\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2$ .