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3 years ago

(1.2 x 10^13) - (4 x 10^11)

Mathematics

1 answer:

Alexandra [31]3 years ago

3 0

Answer:

the answer is 11,600,000,000,000

Step-by-step explanation:

pemdas

(1.2 x 10 ^13) - (4 x 10 ^11)

10^13 = 10,000,000,000,000 put that in scientific notation to make it simpler do same for 10 ^11

10 x 10^13

(1.2 x 10 x 10^13) - ( 4 x 10 x 10^11)

now solve the first equasion

12,000,000,000,000 - 400,000,000,000

subtract

11,600,000,000,000

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The reciprocal parent function is translated 5 units right and 3 units up. Write an equation to represent the new function.

ladessa [460]

Answer:

The new function is $y=\frac{1}{x-5}+3$ , where x ≠ 5

Step-by-step explanation:

The reciprocal parent function is $f(x)=\frac{1}{x}$ , where x ≠ 0

The translation of f(x) to the right h units is f(x - h)

The translation of f(x) up k units is f(x) + k

The translation of f(x) to the right h units and up k units is f(x - h) + k

∵ The equation of the reciprocal parent function is $y=\frac{1}{x}$

∵ The function is translated 5 units right

∴ h = 5

- That means 5 is subtracted from x ⇒ (x - 5)

∵ The function is translated 3 units up

∴ k = 3

- That means y added by 3

∴ $y=\frac{1}{x-5}+3$

The new function is $y=\frac{1}{x-5}+3$ , where x ≠ 5

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3 years ago

The vertex of the parabola is at the point (2,-5). which of the equations below could be the one for this parabola?

timofeeve [1]

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3 years ago

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

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