1. bc/3 + a/xy + 3/ab
= b^2cxya + 3a^2b + 9xy/3xyab
2. (5/3y) + 2y - 12
=11/3y - 2
3. ?
Hope this helps and right! :)) Good luck
Sum/difference:
Let

This means that

Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get

if again we assume x to be rational, we have

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
ANSWER FOR UR QUESTION!
Graph
Find f(f(x))
Describe the Transformation
Find the Domain of the Composition f(f(x))
Solve for x
Solve the System of Equations
Find the Area Between the Curves
Solve by Graphing
Answer:multiple of 3
Step-by-step explanation:
12 is a multiple of 3 so 3 is the Awnser
Let the two numbers be x and y
x + y = 5(x-y)
x + y = 5x -5y
6y = 4x
x= (6/4)y
x= (3/2)y
there the ratio is 3/2