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jonny [76]
3 years ago
7

Formulate a system of equations that could be solved by multiplying one equation by 5 and then adding the two equations together

to eliminate one of the variables.
Mathematics
1 answer:
rjkz [21]3 years ago
4 0
\ \ \ 5 \ (-\frac{1}{5} a = 10 - b) \\ + (2a = 5b -20) \\ \\ a = 30

5× the first equation + the second equation will give an equation of 'a' to its value.
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145 300 610 1230
Vlad1618 [11]
Multiplying by 2 and then adding 10 145*2=290+10=300
300*2=600+10=610
610*2=1220 + 10=1230
x=2 y=10
x+y=12
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4 years ago
Simplify (4x– 4)– 3<br><br><br> A. -1/2x^4<br><br> B. -8x^12<br><br> C. -64x^9<br><br> D. x^12/64
marysya [2.9K]
Use:(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^{-n}=\dfrac{1}{a^n}\\\\\left(4x^{-4}\right)^{-3}=4^{-3}(x^{-4})^{-3}=\dfrac{1}{4^3}x^{-4\cdot(-3)}\\\\=\dfrac{1}{64}x^{12}=\boxed{\frac{x^{12}}{64}}

Answer: D. x^12/64
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Answer:

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Step-by-step explanation:

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