The tower is 61.65 meters tall.
<u>SOLUTION:
</u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,
![2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }](https://tex.z-dn.net/?f=2.5%20%5Cmathrm%7Bm%7D%20%5Ctext%20%7B%20tall%20%7D%20%5Crightarrow%201.47%20%5Ctext%20%7B%20long%20shadow%20%7D)
Then, (let it be) n meter tall
36.25 long shadow
So, by cross multiplication method,
![\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B2.5%7D%7B1.47%7D%3D%5Cfrac%7Bn%7D%7B36.25%7D)
This can be written as,
![\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}](https://tex.z-dn.net/?f=%5CRightarrow%2036.25%20%5Ctimes%202.5%3D1.47%20%5Ctimes%20n%20%5Crightarrow%201.47%20n%3D90.625%20%5Crightarrow%20n%3D61.649%20%5Crightarrow%20n%3D61.65%20%5Ctext%7B%20m%7D)
Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Answer:
you cheater
Step-by-step explanation:
Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson
Answer:
It is unlikely that they will be the same rank 2/52 chance witch is a 0.03% chance
Step-by-step explanation:
Answer:
64? I'm not sure but because if 1= girls (8 girls) and boys is 8 times more you do 8x8 I think sorry if I'm wrong
In decimal form=-7.37
In fraction form plzz refer to the attachment