Answer:
7.21 is write answers brooooooooo
Answer:
at least 5
Step-by-step explanation:
<u><em>If the question was similar to the one given below </em></u>
A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter or a pair of distinct letters written in alphabetical order. What is the least number of letters that can be used if there are 12 participants, and each participant is to receive a different code?
<em><u>The answer would be as follows</u></em>
If we use 3 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
4C2= 6 ways to use these letters and the comma
If we use 4 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
5C2= 10 ways to use these letters and the comma
If we use 5 letters or any distinct letter as a comma such that 2 are in alphabetical order then we would get
6C2= 15 ways to use these letters and the comma
We need the least number of the alphabets to assign codes to 12 participants.
So the least number of alphabets is 5 because it can give codes to at least to 12 people .
Pair of alphabets + distinct letter ≥ 12
5 + 1 ≥ 12
6c2 ≥ 12
15 ≥ 12
Answer:
The answer is A
Step-by-step explanation:
Using PEMDAS you answer parentheses first so
(8-5)2-(2+4) would then be
3*2-6 then you would multiply
6-6 and find the answer of
0
Answer:
-8x +6
Step-by-step explanation:
5x−2 from −3x+4 .
This means take the 2nd number and subtract the 1st
-3x +4
-( 5x -2)
----------------
Distribute the negative sign
-3x +4
- 5x +2
----------------
-8x +6
Answer:
gdfgdf
Step-by-step explanation:
