All categories

3 years ago

What 3 numbers multiply to get 63?

2 answers:

5 0

There are many combinations if the numbers are not required to be integers.

If they are required to be integers, I'd suggest:

3*7*3 = 63

Illusion [34]3 years ago

4 0

63 = 9 * 7

So (3*3) * 7 = 63

<u>The answer is 3 * 3 * 7 = 63</u>

You might be interested in

Use the expression 28b - 4c. Part B: What is the value of the expression when b = -4 and c = 1? Show your work or explain.

Brilliant_brown [7]

Answer:

The value of the expression is -116

Step-by-step explanation:

Given

$Expression: 28b - 4c$

Required

Solve when b = -4 and c = 1

$Expression: 28b - 4c$

Substitute -4 for b and 1 for c

$Expression: 28*-4 - 4*1$

$Expression = -28*4 - 4$

$Expression = =112 - 4$

$Expression: -116$

<em>The value of the expression is -116</em>

3 0

2 years ago

Can someone help me

kakasveta [241]

Answer:

a. 2*-2*3=-12

b. -2*3*5 = -30

c. (-2)^2+2*5= 14

d. 2*-2+3*3-5*5= -20

e. -2(3-5) = 4

f. 3*5-(-2)*5+(-2)*3 = 19

if it helped then plz mark me as brainliest

8 0

3 years ago

57.4 divided by 10???????

Gnesinka [82]

57.4/10=5.74
the answer is 5.74

6 0

3 years ago

Read 2 more answers

Which of the following inequalities is not true?

Lemur [1.5K]

Answer:

$| - 9| = |9|$

This is because modulus number will be always positive

Hope this is correct and helpful

HAVE A GOOD DAY!

4 0

3 years ago

Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d

gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

Step-by-step explanation:

Evaluate:

$\dfrac{b-3a}{bc^{2}-d}$

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\$

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1$

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

6 0

3 years ago