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klasskru [66]
3 years ago
14

Find the equation in slope- intercept from that describes a line through (4,-2) slope-3

Mathematics
1 answer:
tatiyna3 years ago
8 0

Answer:

The answer is: y = -3x + 10

Step-by-step explanation:

Given point: (4, -2)

Given slope: m = -3

Use the point slope form of the equation and substitute:

y - y1 = m(x - x1)

y - (-2) = -3(x - 4)

y + 2 = -3x + 12

y = -3x + 10

Proof:

f(4) = -3(4) + 10

f(4) = -12 + 10

= -2, giving the point (4, -2)

Hope this helps! Have an Awesome Day!! :-)

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Log based question, i just need help with parts b and c
Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

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Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

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- If the function f(x) translated vertically up  

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- If the function f(x) translated vertically down  

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* Now lets solve the problem

b) ∵ f(x) = log_{2} (x-3)+1

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  to the right

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    make the function undefined

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* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

  and the equation of the asymptote

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