C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
The answer is A. Working the formula backwards you get that r^2=256, so r=16
35 + 15 x 4 = 60. Paola read 60 pages in total.
The answer is 4480 hope it helps
Y = 2 because half of 10 is 5 so half of 4 is 2