The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
<h3>
Which points are solutions of the inequality?</h3>
We want to find points of the form (x, y) that are solutions of the inequality:
x*y > 0
Clearly x and y must be different than zero.
So, for example if x = -1, y can be any negative number, for example y= -3
x*y > 0
(-1)*(-3) > 0
3 > 0
This is true.
Now if x = 1, y must be positive. LEt's take y = 103, then:
x*y > 0
1*103 > 0
103 > 0
Then we have 3 conditions:
- x ≠ 0
- y ≠ 0
- Sign(x) =sign(y)
The solutions fo the inequality are all the points (x, y) that meet these 3 conditions.
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Answer:
(-9) + (-2) = -11
Step-by-step explanation:
The first arrow on the number line starts from 0, moves downwards 9 units from 0.
We would write this as -9.
Also, the next arrow starts moves from -9, 2 units downwards.
We would write this as -2
The addition equation would be:
(-9) + (-2) = -11
(Credit goes to google)<span>f ( x ) = a </span>x<span>. where x is a variable, and a is a constant called the base of the </span>function<span>. The most commonly encountered </span>exponential-function<span> base is the transcendental number e , which is equal to approximately 2.71828.</span>
Well the answer is either Jesus or applesauce
Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
mixas84 [53]
The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A
<h3>Algebra</h3>
2^x - 2
when x = 0
2^x - 2
= 2^0 - 2
= 1 - 2
= -1
when x = 1
2^x - 2
=2^1 - 2
= 2 - 2
= 0
when x = 2
2^x - 2
= 2^2 - 2
= 4 - 2
= 2
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