1. What is the circumference of the circle below? 11 cm
1 answer:
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Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
B
Step-by-step explanation:
The sections of the parallel roads split by the transversals are in proportion, that is
=
( cross- multiply )
300 first = 577500 ( divide both sides by 300 )
first = 1925 ft
Thus
Elm st → Maple st = 1925 + 350 = 2275 ft → B