3 years ago

THE QUESTION IS BELOW. PLEASE HELP ME ANSWER IT, I AM TIMED.

Mathematics

1 answer:

katrin2010 [14]3 years ago

3 0

The answer should be A

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Is the given pair a solution y=-x -2; (2,-4)

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Step-by-step explanation:

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2 years ago

Read 2 more answers

How do you solve for a and b showing your work

Mariulka [41]

Answer:

a) 4

b) $\frac{1}{2} \sqrt{y^5}$

Step-by-step explanation:

PART A

Simplify the expression by solving out the square roots.

$\frac{\sqrt{16} \sqrt{p} }{\sqrt{p}}$ = $\frac{4 \sqrt{p} }{\sqrt{p}}$

You can cancel out the $\sqrt{p}$ on the top and bottom.

So, a should be 4.

PART B

Solve out the square root. The square root is pretty much the 1/2 power, so you can divide the exponents by half.

$\frac{\sqrt{y^{10}} }{\sqrt{4y^{5}} }$ = $\frac{y^{5}}{2y^{\frac{5}{2}} }$

You can subtract exponents to divide them. So the y variable becomes $y^{5 - 5/2}$ , or $y^{5/2}$ .

Then, the overall expression is $\frac{1}{2} y^{\frac{5}{2} }$ , or you can turn that into $\frac{1}{2} \sqrt{y^5}$ .

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3 years ago