The decimal approximation for the trigonometric function sin 28°48' is
Given the trigonometric function is sin 28°48'
The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.
To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°
sin (28°48') = sin(28° ₊ (48 × 1/60)°)
= sin(28° ₊ (48 /60)°)
= sin(28° ₊ 4°/5)
= sin(28° ₊ 0.8°)
= sin(28.8°)
= 0.481753
Therefore sin (28°48') is 0.481753.
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Answer:
you gotta go to school
Step-by-step explanation:
Answer:
This would mean 3x=5
so to isolate the x, we divide 5 by 3
and get x=5/3
Answer:
The equation of the sraight line 3x- y+ 6 =0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the gradient of the function
|gradf| = 3 and point (-1,3)
Given that the slope of the line
m = 3
The equation of the straight line passing through the point(-1,3) and slope m =3
y-3 = 3(x-(-1))
y-3 = 3x+3
3x +3-y+3=0
3x- y+ 6 =0
<u><em>Final answer:-</em></u>
The equation of the sraight line 3x- y+ 6 =0
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