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tatiyna
3 years ago
8

Integrate xcos(5x)

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0
I think that you have wrong u-substitution ( partial integration ):\int {u} \, dv= uv- \int {v} \, du
u=x,           dv=cos 5x dx
du=dx,       v=1/5 * sin 5x
Integral becomes:= \frac{xsin 5x}{5}- \int { \frac{1}{5} sin 5x} \, dx= \\ = \frac{xsin5x}{5}- \frac{1}{5}    (- \frac{1}{5}cos5x)= \frac{x sin5x}{5}+ \frac{cos5x}{25} +C
Is it OK now? 
pentagon [3]3 years ago
5 0
Hello,

\int{x*cos(5x)} \, dx=x*\frac{sin(5x)}{5}- \frac{1}{5}*\int{sin 5x} \, dx\\=\frac{x*sin(5x)}{5}+\frac{cos(5x)}{25}+c


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6 0
3 years ago
The width of a rectangle is 3 feet less than it’s length. The perimeter of the rectangle is 98 feet. Find the dimensions of the
horsena [70]

Answer:

The length is 26 feet and the width is 23 feet

Step-by-step explanation:

Let l represent the length of the rectangle.

The width can be represented by l - 3, since it is 3 feet less than the length

Set up an equation:

l + l + (l - 3) + (l - 3) = 98

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Since the width is l - 3, we can plug this in for l to find the width:

l - 3

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4 0
3 years ago
TWO EASY QUESTIONS 8TH GRADE MATH
Sophie [7]
9.
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11.
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3 years ago
Read 2 more answers
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