Answer: There is no solution to this
Step-by-step explanation:
Answer:
a) P(z<-0.66) = 0.2546
b) P(-1<z<1) = 0.6826
c) P(z>1.33) = 0.9082
Step-by-step explanation:
Mean = 300
Standard Deviation = 75
a) Less than 250 hours
P(X<250)=?
z = x - mean/ standard deviation
z = 250 - 300 / 75
z = -50/75
z = -0.66
P(X<250) = P(z<-0.66)
Looking for value of z = -0.66 from z score table
P(z<-0.66) = 0.2546
b. Between 225 and 375 hours
P(225<X<375)=?
z = x - mean/ standard deviation
z = 225-300/75
z = -75/75
z = -1
z = x - mean/ standard deviation
z = 375-300/75
z = 75/75
z = 1
P(225<X<375) = P(-1<z<1)
Looking for values from z score table
P(-1<z<1) = P(z<1) - P(z<-1)
P(-1<z<1) = 0.8413 - 0.1587
P(-1<z<1) = 0.6826
c. More than 400 hours
P(X>400) =?
z = x - mean/ standard deviation
z = 400-300/75
z = 100/75
z = 1.33
P(X>400) = P(z>1.33)
Looking for value of z = 1.33 from z-score table
P(z>1.33) = 0.9082
Part A
Yes y is a function of x. Specifically the equation is y = x^5
For any given input, there is exactly one output
Notice how if x = 1 then y = x^5 = (1)^5 = 1
Notice how if x = -1 then y = x^5 = (-1)^5 = -1
Notice how if x = -2 then y = x^5 = (-2)^5 = -32
Notice how if x = 2 then y = x^5 = (2)^5 = 32
In general,
x^5 = x*x*x*x*x
there are five copies of x multiplied
A more specific example
3^5 = 3*3*3*3*3
there are five copies of '3' multiplied
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Part B
All we do is replace x with 4 and use PEMDAS to simplify
f(x) = 2x+12
f(4) = 2(4)+12
f(4) = 8+12
f(4) = 20
The value of f(4) is 20
What does it mean? It is the total cost of renting the bowling lane for 4 hours. If you rent it for four hours, then you'll pay a total of $20.
The portion 2x = 2*4 = 8 is the variable cost which depends on how long you play. The more hours, the more the variable cost goes up
The fixed cost is 12. This is always fixed as this is the price to get in the door. If you play for 0 hours, but somehow got in the door, then you still pay $12
In total, variableCost+fixedCost = 8+12 = 20 = totalCost
solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Okay so basically you will need two sets of working out.
Sandra:
I=PRN
=14000x7x0.045
=4410
Cindy:
I=PRN
=14000x7x0.06
=5880
5880-4410
=1470
Therefore, Cindy earnt $1470 more than Sandra after 7 years.