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tatuchka [14]
3 years ago
14

What is the value of x in the equation x – y = 30, when y = 15?

Mathematics
2 answers:
stellarik [79]3 years ago
8 0
X=45. If y is 15 and x-y =30. Then 30+15=45 so x is 45.
iogann1982 [59]3 years ago
5 0
The answer is 45, because if you have 45(x)-15(y)=30
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Which equation does not represent a linear function of x?
Natasha_Volkova [10]
The answer is D) y = 3x^2 - 2, because the x is squared, making the function a quadratic function. Quadratic functions will be in the shape of a parabola (a u or upside down u). 

Meanwhile any function whose degree (highest exponent of x) is one is a linear function. It will have be a straight line.
5 0
3 years ago
In a company, 80% of the workers are women. if 880 men work for the company, how many workers are there in all?
ELEN [110]
If 80% are women, then 20% are men

20% of what equals 880
0.20x = 880
x = 880/.20
x = 4400

check..
men : 20% of 4400 = 0.20(400) = 880
women : 80% of 4400 = 0.80(4400) = 3520
totaling : 3520 + 880 = 4400

so there are a total of 4400 workers

6 0
3 years ago
If the number of people is greater than the number of segments each person will get less than one segment
babymother [125]
Is this even a question, it seems to be more of a statement..
3 0
3 years ago
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solut
Norma-Jean [14]

Differentiate the given solution:

x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)

Now, given that <em>x</em> (<em>π</em>/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)

\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1+C_2=1

Similarly, given that <em>x'</em> (<em>p</em>/4) = 0, you have

0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)

\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1=C_2

From this result, it follows that

C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12

So the particular solution to the DE that satisfies the given conditions is

\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7Bx%20-%201%7D%5E%7B2%7D%20%20-%204" id="TexFormula1" title="f(x) = {x - 1}^
Hoochie [10]

Answer: x = 5

Step-by-step explanation:

5 0
3 years ago
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