Answer:
x ≤ 12.83
(Any number under or equal to 12.8333...)
Step-by-step explanation:
154 ≥ 12x
12.833.... ≥ x
x ≤ 12.83
Answer:
The diagonals of an isosceles trapezoid are congruent.
The bases of a trapezoid are parallel.
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
The discriminant is b<span>²-4ac
We can rewrite x</span>² = 4 to x<span>² + 0x - 4 = 0
So a = 1, b = 0, c = -4
</span>Δ = 0 - 4 * 1 * -4
Δ = 16
The answer is B
Answer:
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Step-by-step explanation:
Required
Show that:
To make the proof easier, I've added a screenshot of the triangle.
We make use of alternate angles to complete the proof.
In the attached triangle, the two angles beside 
are alternate to 
and 
i.e.
Using angle on a straight line theorem, we have:
Substitute values for (1) and (2)
Rewrite as:
<em></em><em> -- proved</em>
