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galina1969 [7]
3 years ago
12

Find the cost per roll if a bag of five lunch rolls is $2.50.

Mathematics
1 answer:
Andru [333]3 years ago
5 0
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50 </em></u></h3><h3><u><em> 2 lunches = $5.00 (2.50x2) </em></u></h3><h3><u><em> 3 lunches =$7.50 </em></u></h3><h3><u><em> 4 lunches =$10.00 </em></u></h3><h3><u><em> 5 lunches= $12.50 </em></u></h3><h3><u><em> Just add $2.50</em></u></h3>
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Susan needs 228 ounces of fruit juice for a party. She is choosing between two brands of juice. She finds the unit rate of each
Sergio [31]

Answer:

"Brand A costs approximately $0.21 per ounce, and Brand B costs approximately $0.18 per ounce."

In order to find the rounded cost per one item (in this case, per one ounce) Susan needs to divide the total price between the number of units and after that, round the result obtained up to the nearest cent.

Therefore:

Brand A

2.55$/12 ounces= 0.2125 $/ounce

As the third decimal digit, 2, is closer to 0 than to 9, then we maintain the second decimal digit as 1.

The price per unit of brand A after rounding it up is 0.21 $ per ounce

Brand B

1.45$/8 ounces= 0.1812

As the third decimal digit, 1, is closer to 0 than to 9, then we maintain the second decimal digit as 8.

The price per unit of brand B after rounding it up is 0.18 $ per ounce

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3 years ago
Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

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Answer: no solution

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