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mihalych1998 [28]
3 years ago
13

How to get 1/5 of 30

Mathematics
1 answer:
marin [14]3 years ago
5 0
\frac{1}{5} of 30
= Convert of to multiplication;
\frac{1}{5} *30
=6
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Which set is an example of like fractions? A. 2⁄1 and 2⁄3 B. 1⁄2 and 3⁄2 C. 7⁄4 and 4⁄7 D. 10⁄10 and 5⁄5
Sloan [31]
<span>Fractions which have the same denominator are called like fractions.
</span>The answer is B. 1⁄2 and 3⁄2
5 0
4 years ago
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Solve the equation log4(x + 20) = 3
mixas84 [53]

Answer:

I don't think it's possible to add a number to 20 and then multiply it by 4 and get 3.

Step-by-step explanation:

7 0
3 years ago
0.5% of what number is 12?
satela [25.4K]

Answer:

2400

Step-by-step explanation:

Step 1: Turn 0.5 into a whole number.

  • 0.5 * 10
  • 5

Step 2: Divide 12 by 5.

  • 12/5
  • 2.4

Step 3: Multiply 2.4 by 1000

  • 2.4 * 1000
  • 2400

Therefore, the answer is 2400.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
2 years ago
If AD/DB = AE/EC, then line segment (?) is parallel to line segment (?) .
olga_2 [115]

Answer:

Step-by-step explanation:

In ΔABC, we have

\frac{AD}{DB}=\frac{AE}{EC}

The Converse of the basic proportionality theorem states that if a line divides two sides of a triangle in same ratio then the line must be parallel to the third side.

Now, it is given that \frac{AD}{DB}=\frac{AE}{EC}, this implies that line segment DE divides AB and AC in the same ratio.

Thus, by converse of basic proportionality theorem  

line segment DE= line segment BC.

Therefore, if  \frac{AD}{DB}=\frac{AE}{EC},then line segment DE is parallel to line segment BC .

4 0
3 years ago
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a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution
Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

.

Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25

We can calculate the probability of getting one non-conforming units (k=1) as:

P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51

5 0
4 years ago
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