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artcher [175]
2 years ago
6

-8m+(-15)+4m-2r-10 ?

Mathematics
1 answer:
AVprozaik [17]2 years ago
7 0

Answer:

- 4m - 2r - 25

Step-by-step explanation:

-8m + (-15) + 4m - 2r - 10

- 8m - 15 + 4m - 2r - 10

collect the like terms beginning with the positives

4m - 8m - 2r - 10 - 15

- 4m - 2r - 25

You might be interested in
2. (10.03)
faust18 [17]

This question is incomplete because it was not written properly

Complete Question

A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)

a) 20%

b) 40%

c) 60%

d) 75%

Answer:

d) 75%

Step-by-step explanation:

We would be solving this question using conditional probability.

Let us represent the percentage of those who passed the first quiz as A = 80%

and

Those who passed the first quiz as B = unknown

Those who passed the first and second quiz as A and B = 60%

The formula for conditional probability is given as

P(B|A) = P(A and B) / P(A)

Where,

P(B|A) = the percent of those who passed the first one passed the second

Hence,

P(B|A) = 60/80

= 0.75

In percent form, 0.75 × 100 = 75%

Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.

3 0
3 years ago
Factor 5(2x+7)+4(2x+7)<br>enter your answer in the box​
AfilCa [17]

Answer:

18x+63

Step-by-step explanation:

First you've to simplfy it, multiply the first bracket by 5 and the second by 4.

= (5)(2x)+(5)(7) + (4)(2x)+(4)(7)

= 10x+35+8x+28

Combine Like Terms:

= 10x+35+8x+28

= (10x+8x)+(35+28)

= 18x+63

6 0
3 years ago
Read 2 more answers
What is the media of 9,3,10,12,4,5,12,2
HACTEHA [7]

Answer:

The median is 7

8 0
3 years ago
Read 2 more answers
Consider the toss of four coins. There are 16 (i.e., 24) possible outcomesin one toss. (a)Calculate the probabilities that there
lana [24]

Answer:

See answers below

Step-by-step explanation:

If 4 coins are tossed. the total possible outcomes are;

H H H H , H H H T, H H T H, H T H H, T H H H , H H T T, H T T H, T T H H, H T H T, T H T H, T H H T , H T T T, T H T T, T T H T, T T T H  and T T T T

Total outcomes = 16

1) zero head = T T T T = 1 outcome

Probability = Expected/Total outcome

Pr(zero head) = 1/16

2) one head = H T T T, T H T T, T T H T, T T T H   = 4 outcomes

Probability = Expected/Total outcome

Probability = 4/16

Pr(one head) = 1/4

3) two heads = H H T T, H T T H, T T H H, H T H T, T H T H, T H H T   = 6 outcomes

Probability = Expected/Total outcome

Pr(two head) = 6/16

Pr(two head) = 3/8

4)  three heads = H H H T, H H T H, H T H H, T H H H   = 4 outcomes

Probability = Expected/Total outcome

Pr(three heads) = 4/16

Pr(two head) = 1/4

5) four heads appearing on the four coins =  H H H H = 1 outcome

Pr(four heads) = 1/16

6 0
3 years ago
How to solve for x?
mote1985 [20]

Answer:

159

Step-by-step explanation:

35x-1 =-35 plus 34x20

5 0
3 years ago
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