Answer:
a+0 (or just 0)
Step-by-step explanation:
The additive identity is when you add any number by zero. This is because an additive identity is what number do you add to make the same number (since it's additive it is zero, if it were multiplicative, it'd be 1)
12+12m= 75+ 10m
2m = 63
M= 31.5
Answer:
2884
Step-by-step explanation:
First plug in -10 for x, which would look like this: 734 + (-215 * (-10) ) =
Then, first you calculate everything in the parenthesis, which is (-215) * (-10)
and the equation would look like this after you multiply: 734 + 2150 =
If you noticed the number turned out positive after we multiplied, that is because - number times a - number would always be positive, just like if you divide - number by a - number your answer would be positive.
Your last step would be adding 734 with 2150. : 734 + 2150 = 2884
+ 734
2150
_____
2884
And the answer would be 2884
Answer:
y = 2x + 1 ;
y - 3 = - 3(x - 1) ; y = - 3x + 6 ;
Step-by-step explanation:
Given the data:
Sidewalk 1:
x __ y
2 _ 5
0 _ 1
Sidewalk 2:
x __ y
1 _ 3
3 _ -3
Equation for sidewalk 1 in slope - intercept form:
Slope intercept form:
y = mx + c
c = intercept ; m = slope
m = (change in y / change in x)
m = (1 - 5) / (0 - 2) = - 4 / - 2 = 2
Y intercept ; value of y when x = 0
(0, 1) ; y = 1
Hence, c = 1
y = 2x + 1
Sidewalk 2:
Point slope form:
y - y1 = m(x - x1)
m = slope
m = = (-3 - 3) / (3 - 1) = - 6/2 = - 3
Point (x1, y1) = (1, 3)
y - 3 = - 3(x - 1)
To slope intercept form:
y - 3 = - 3(x - 1)
y - 3 = - 3x + 3
y = - 3x + 3 + 3
y = - 3x + 6
Since the slope of both lines are different, intersection will be at single point and will have a single solution. This makes it independent.
Using substitution method :
y = 2x + 1 - - - (1)
y = - 3x + 6 - - - (2)
Substitute (1) into (2)
2x + 1 = - 3x + 6
2x + 3x = 6 - 1
5x = 5
x = 1
From (1)
y = 2(1) + 1
y = 2 + 1
y = 3
Coordinate of the point of intersection = (1, 3)
Answer:
![\displaystyle 11,3](https://tex.z-dn.net/?f=%5Cdisplaystyle%2011%2C3)
Step-by-step explanation:
Use the Law of Cosines to find the length of the third edge:
<em>Solving for Angles</em>
![\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos\angle{C} \\ \frac{a^2 - b^2 + c^2}{2ac} = cos\angle{B} \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos\angle{A}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Ba%5E2%20%2B%20b%5E2%20-%20c%5E2%7D%7B2ab%7D%20%3D%20cos%5Cangle%7BC%7D%20%5C%5C%20%5Cfrac%7Ba%5E2%20-%20b%5E2%20%2B%20c%5E2%7D%7B2ac%7D%20%3D%20cos%5Cangle%7BB%7D%20%5C%5C%20%5Cfrac%7B-a%5E2%20%2B%20b%5E2%20%2B%20c%5E2%7D%7B2bc%7D%20%3D%20cos%5Cangle%7BA%7D)
Use
towards the end or you will throw your result off!
<em>Solving for Edges</em>
![\displaystyle b^2 + a^2 - 2ba\:cos\angle{C} = c^2 \\ c^2 + a^2 - 2ca\:cos\angle{B} = b^2 \\ c^2 + b^2 - 2cb\:cos\angle{A} = a^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b%5E2%20%2B%20a%5E2%20-%202ba%5C%3Acos%5Cangle%7BC%7D%20%3D%20c%5E2%20%5C%5C%20c%5E2%20%2B%20a%5E2%20-%202ca%5C%3Acos%5Cangle%7BB%7D%20%3D%20b%5E2%20%5C%5C%20c%5E2%20%2B%20b%5E2%20-%202cb%5C%3Acos%5Cangle%7BA%7D%20%3D%20a%5E2)
Take the <em>square root</em> of the final result or it will be thrown off!
Let us get to wourk:
![\displaystyle 10^2 + 7,9^2 - 2[10][7,9]\:cos\:77,5 = a^2 \hookrightarrow 100 + 62,41 - 158\:cos\:77,5 = a^2 \hookrightarrow \sqrt{128,212541} = \sqrt{a^2}; 11,323097677... \\ \\ \boxed{11,3 \approx a}](https://tex.z-dn.net/?f=%5Cdisplaystyle%2010%5E2%20%2B%207%2C9%5E2%20-%202%5B10%5D%5B7%2C9%5D%5C%3Acos%5C%3A77%2C5%20%3D%20a%5E2%20%5Chookrightarrow%20100%20%2B%2062%2C41%20-%20158%5C%3Acos%5C%3A77%2C5%20%3D%20a%5E2%20%5Chookrightarrow%20%5Csqrt%7B128%2C212541%7D%20%3D%20%5Csqrt%7Ba%5E2%7D%3B%2011%2C323097677...%20%5C%5C%20%5C%5C%20%5Cboxed%7B11%2C3%20%5Capprox%20a%7D)
I am joyous to assist you at any time.