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Otrada [13]
3 years ago
7

Which decimal is largest 0.03 0.3 0.29 or 0.039

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
0.3 would be the largest decimal
Pavel [41]3 years ago
3 0
0.3, because it is the closest to one.
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1. According to a recent survey, 13 out of the 33 students in a class take the bus to school. What is the ratio of students who
AlexFokin [52]

Answer: (1) 13/20    (2) 8    (3) Yes. They are proportional

<u>Step-by-step explanation:</u>

(1) 13 students take the bus.

   33 - 13 = 20 students do not take the bus

    \dfrac{\text{take the bus}}{\text{do not take the bus}}:\dfrac{13}{20}

(2)

\dfrac{2\ red}{3\ green}=\dfrac{x}{12\ green}\\\\\\\underline{\text{cross multiply}:}\\2(12)=3(x)\\24=3x\\8=x

(3)

\dfrac{6}{10}\div \dfrac{2}{2}\quad =\dfrac{3}{5}\\\\\\\dfrac{9}{15}\div \dfrac{3}{3}\quad =\dfrac{3}{5}\\\\\\\dfrac{15}{25}\div \dfrac{5}{5}\quad =\dfrac{3}{5}

All of the fractions simplify to the same number so they ARE proportional.

4 0
3 years ago
13. John and Jane ate lunch at a local restaurant and wanted to divide the bill evenly. The
postnew [5]
John will receive $9.80 back
6 0
3 years ago
What’s X and how did you find it?
Gre4nikov [31]

Answer:

X=12

Step-by-step explanation:

2/3x-5=1/2x-3

2/3x=1/2x+2

2/3x-1/2x=2

(6)1/6x=2(6)

X=12

I am not sure

8 0
4 years ago
A------------------ does not have an apex.<br><br> prism<br> cone<br> pyramid
Kaylis [27]
A prism does not have an apex.

An apex is the highest point of an object.
3 0
4 years ago
Read 2 more answers
Find the polynomial equation of lowest degree, with real coefficients and leading coefficient 1 1 that has the given roots.
Andreyy89

Answer:

x^4 + 2x^3 + 3x^2 + 2x + 2 = 0

Step-by-step explanation:

The computation of the polynomial equation of the lowest degree is shown below

As we know that the complex roots would always arise in the conjucate pairs

As -i is a root, i is also a root

As  -1 + i is a root

And, -1 is also a root

Now the polynomial equation would be

(x + i)(x - i)(x + 1 - i)(x + 1 - i) = 0

(x^2 - i^2)[(x + 1)^2 - i^2] = 0

(x^2 + 1)[(x + 1)^2 + 1] = 0

(x^2 + 1)(x^2 + 2x + 2) = 0

x^4 + 2x^3 + 3x^2 + 2x + 2 = 0

6 0
3 years ago
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