Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Z-m=z+bx
z-m-z=z+bx-z
-m=bx
bx=-m
bx/b=-m/b; b=0
x=-m/b; b=0
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The square root of 16 is 4
Answer:
B.
Step-by-step explanation:
