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sashaice [31]
3 years ago
10

What percent of 48 is 30

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
The answer is 14.4% I just did it in my head
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A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the
aleksandrvk [35]
<h2>PLEASE MARK ME AS BRAINLIEST</h2>

the number of small cars rented is 6.

The number of large cars rented is 8.

Step-by-step explanation:

Step 1 :

Each small car can hold = 5 people

Each large car can hold  = 8 people

Step 2 :

Number of small cars rented = x

Number of large cars rented = x + 2

Step 3 :

Altogether the total cars can hold 94 people.

Total people = 5 people (No. of small cars) + 8 people (No. of large cars)

               94 =  5 (x) + 8 (x+2)

               94 = 5x + 8x + 16

               78 = 13x

                  x = 78/13 = 6

∴ Number of small cars, x = 6 small cars

  Number of large cars, x+2 = 8 large cars.

8 0
3 years ago
Ayuda 7×9÷2=<br><br><br><br>note : btw how to get rid of this ad ?​
JulijaS [17]

Step-by-step explanation:

7×9÷2

By using the rule of BODMAS , we get

7×9÷2

7×4.5

31.5

5 0
2 years ago
Read 2 more answers
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
Solve this equation 3x + 5 = 7x – 7
Mama L [17]
Add 7 to both sides
3x + 12 = 7x
Subtract 3x
12 = 4x
Divide by 4
x = 3
4 0
3 years ago
Read 2 more answers
For what value n is 1P3 =nP4?
Serggg [28]

Answer:

I don't know if this helps, just a picture not a link

3 0
3 years ago
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