Answer:
Because θ lies in quadrant II, 2θ must lie in quadrant IV. This means the tangent of 2θ is negative.
The adjacent side to θ is 7 because √(25²-24²)=7, so tanθ=7/24.
The double angle formula for tangent is tan 2θ = (2 tan θ) / (1 − tan² θ).
Substituting the value for tanθ in and keeping in mind that this is in quadrant IV, we get tan 2θ = -(2(7/24)/(1-(7/24)²)).
Simplified, this becomes tan 2θ = -336/527.
Therefore, the answer is C. -336/527.
The Formula to find the Area of a circle using the radius is:
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20r%5E2)
r = 8
So:
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20r%5E2)
![A = \pi 8^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%208%5E2)
![A = \pi64](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi64)
And you get about 201.06193
So, the area of a circle with a radius of 8 is about 201.06
Hope this Helps :)
Answer:
The 4 interior angles in the square are each 90 degrees. The four angles formed by the intersection of the 2 diagonal lines are each 90 degrees. The rest of the angles <PQT, <RQT, etc. Are all 45 degrees.