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irina1246 [14]
3 years ago
7

Which equation can be used to solve for "X"?

Mathematics
1 answer:
ipn [44]3 years ago
5 0

Answer:

im going to tell the teacher for cheating

Step-by-step explanation:

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Jack is playing a game. When a player wins 3 consecutive games, the player receives 10 bonus points and then the player’s total
Paladinen [302]
<span>The function can be described as

b(p)= player receives 10 bonus points 
</span>b(p)= p+10<span>

s(p)= increases 5% of the player’s current points 
</span>s(p)= <span>p*(100%+5%)= p*1.05

then </span><span> (s ∘ b)(p) would be
</span><span>s(p)= p*1.05
(s ∘ b)(p)= (p+10)*1.05
</span>(s ∘ b)(p)= 1.05p+10.5
4 0
3 years ago
In which quadrant is the value of the x-coordinate of a point on the unit circle always greater than the y-coordinate?
Yuliya22 [10]

Answer:

IV

In the fourth quadrant (IV).

Step-by-step explanation:

In the IV quadrant the x coordinate is always positive and the y coordinate is always negative. So the x coordinate is always larger than the y coordinate.

4 0
1 year ago
A ball is thrown from a height of 40 meters with an initial downward velocity of 5 m/s
arsen [322]

0=40-10t-5t^2

t^2+2t-8=0

(t+4)(t-2)=0

t=-4 (not a solution) or t=2

Answer: after 2 seconds

7 0
3 years ago
Train X is traveling at a constant speed of 30 miles per hour and Train Y is traveling at a constant speed of 40 miles per hour.
topjm [15]

Answer:

3.5 hours

Step-by-step explanation:

Speed of train X=30 mph

Speed of train Y=40  mph

Relative speed When the two trains travelling in same direction

Relative speed=40-30=10 mph

Total distance =25+10=35 miles

We have to find the time when train Y is 10 miles ahead of train X.

We know that

Time=\frac{Distance}{Relative\;speed}

Using the formula

Then, we get

Time=\frac{35}{10}=3.5 hours

Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.

7 0
3 years ago
Read 2 more answers
You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?
Rasek [7]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}

\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61

5 0
2 years ago
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