Answer:
2
Step-by-step explanation:
You count terms that are seperated by - and + signs. Any type of fraction is considered one term.
So you count 8y as one term and the rest is a whole fraction so you also count that as one term.
You add all the terms together and you have 2 terms in this equation.
Hope this helped :)
Answer:
only a
Step-by-step explanation:
Answer:
1620
Step-by-step explanation:
The amount of even integers between 10 and 80 inclusive is 36 (5 for each interval of 10 [e.g., 10-19 has 5, 20-29 has 5] and one extra for 80).
Since the numbers are consecutive even numbers, we can use the fact that the sum of the numbers is equal to the average of the numbers, times the number of numbers.
The average of the numbers is 45, since
. We can use only the two outer numbers to determine the average since the numbers are all evenly spaced as they are consecutive even numbers.
, so the sum is 1620.
Answer:
167,886,383 basketballs
Step-by-step explanation:
We are asked to find how many basketballs would take to circle around the equator. We have given the earth's radius. So, we need the formula to obtain it's perimeter. Thus:
![Perimeter = Pi*diameter [m]\\Where Pi = 3.14](https://tex.z-dn.net/?f=Perimeter%20%3D%20Pi%2Adiameter%20%5Bm%5D%5C%5CWhere%20Pi%20%3D%203.14)
Earth's diameter is simply radius*2. It means:
![P= 3.14*6400*2 = 40,192 [km]](https://tex.z-dn.net/?f=P%3D%203.14%2A6400%2A2%20%3D%2040%2C192%20%5Bkm%5D)
On the other hand, we have a basketball crcumference; however, we need to obtain its diameter so that we can later calculate how many basketballs fit on earth's equator by simply dividing earth's circumference by a basketball's diameter.
Diameter of a basketball:
![D= Perimeter /Pi [m]](https://tex.z-dn.net/?f=D%3D%20Perimeter%20%2FPi%20%5Bm%5D)
We need to change units to fit in the international system.
29.6 in to cm = ![29.6*2.54 = 75.184 [cm]](https://tex.z-dn.net/?f=29.6%2A2.54%20%3D%2075.184%20%5Bcm%5D)
Then:
![Diameter=75.184/3.14 = 23.94 [cm]](https://tex.z-dn.net/?f=Diameter%3D75.184%2F3.14%20%3D%2023.94%20%5Bcm%5D)
We have to convert earth's perimeter in km to cm:
![Equator=40192[km]*100000=4,019,200,000 [cm]](https://tex.z-dn.net/?f=Equator%3D40192%5Bkm%5D%2A100000%3D4%2C019%2C200%2C000%20%5Bcm%5D)
Finally, dividing total earth's circumference by a basketball diameter:
![Totalbasketballs=4,019,200,000/23.94= 167,886,383 [basketballs]](https://tex.z-dn.net/?f=Totalbasketballs%3D4%2C019%2C200%2C000%2F23.94%3D%20167%2C886%2C383%20%5Bbasketballs%5D)
Answer:

And for this case we can use the cumulative distribution function given by:

And using this formula we have this:

Then we can conclude that the probability that your bid will be accepted would be 0.41
Step-by-step explanation:
Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:

If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:

And for this case we can use the cumulative distribution function given by:

And using this formula we have this:

Then we can conclude that the probability that your bid will be accepted would be 0.41