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stiv31 [10]
2 years ago
15

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

e highest bid in excess of $10,100 will be accepted. Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,100 and $14,700. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)
Mathematics
1 answer:
Alik [6]2 years ago
8 0

Answer:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

Step-by-step explanation:

Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:

X \sim Unif( a= 10100, b =14700)

If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:

P(X

And for this case we can use the cumulative distribution function given by:

P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b

And using this formula we have this:

P(X

Then we can conclude that the probability that your bid will be accepted would be 0.41

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