Ask question

Ask question

All categories

2 years ago

11

A triangular prism is 20 millimeters long and has a triangular face with a base of 24 millimeters and a height of 16 millimeters

. The other two sides of the triangle are each 20 millimeters. What is the surface area of the triangular prism?

1 answer:

uysha [10]2 years ago

7 0

Answer:

The surface area of the prism is $1,664\ mm^{2}$

Step-by-step explanation:

we know that

The surface area of the triangular prism is equal to

$SA=2B+PL$

where

B is the area of the triangular face

P is the perimeter of the triangular face

L is the length of the triangular prism

<em>Find the area of the triangular face B</em>

$B=\frac{1}{2}(24)(16)= 192\ mm^{2}$

<em>Find the perimeter of the triangular face P</em>

$P=(24+20+20)= 64\ mm$

we have

$L=20\ mm$

substitute the values

$SA=2(192)+(64)(20)=1,664\ mm^{2}$

You might be interested in

What is the height of the trapezoid ? A) 3units B) 5units C) 10units D) 12units

zheka24 [161]

Answer:

b) 5

Step-by-step explanation:

6+10=16

40 times 2 = 80

80 div by 15 = 5

5 0

2 years ago

Read 2 more answers

A plane can fly 7 miles per minute. The plane will fly 8 trips, and each trip is 810 miles. How many hours will the plane fly? S

ELEN [110]

7*60 = 420

810/420 = 1.9285

93- 100 = 53-60

subtract 40 from 93.

1.53*8 = 12.24

Answer: 12 hours and 24 Minutes

If this helps give a brainliest :)

4 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0

2 years ago

IF CORRECT I WILL GIVE BRAINLY I NEED HELP ASAP

Dafna11 [192]

1 question what is x equal to?

8 0

2 years ago

Read 2 more answers