I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
Answer:
½ ln 3
Step-by-step explanation:
∫ sec²x / tan x dx
If u = tan x, then du = sec²x dx.
∫ du / u
ln|u| + C
ln|tan x| + C
Evaluate between π/4 and π/3.
ln|tan(π/3)| + C − (ln|tan(π/4)| + C)
ln|√3| + C − ln|1| − C
ln(√3)
½ ln 3
Answer:
The area that she painted = 896 mm^2
Step-by-step explanation:
Given:
The given figure is a pyramid with square base.
Here we need to find the surface area of the figure that need to be painted.
Surface area of a square pyramid = (S×S) + 2×S×L square.units
Where, S = side of the base L = slant height of the pyramid.
Now we have to plug in the given values.
Here S = 14, L =25
Plug in these values into the formula
= (14*14) + 2*14*25
= 196 + 700
= 896 mm^2
The area that she painted = 896 mm^2
Hope this will helpful.
Thank you.
Answer:
1. y=3x-2 -> x= (y+2)/3
Step-by-step explanation:
You simply sub-in the m and b, then "reverse" the problem by doing the steps to get from the 2nd, to the first.
Answer:
-7/6
Step-by-step explanation:
To evaluate this, start by turning each into improper fractions.
3 1/2 - 4 2/3
7/2 - 14/3
Now give both common denominators and complete the operation.
7/2 - 14/3
21/6 - 28/6
-7/6
