Please, do not post more than 1 or 2 questions at a time. Out of courtesy I will address one of your six questions here:
<span>2x + 4 = 3(x – 2) + 1
You are to solve this for x.
1) perform the multiplication: </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms: 4+6-1 = x
3) solve for x: x = 11
4) check: Is 2(11) + 4 = 3(11-2) + 1 true?
Is 22+4 = 33-6 true? NO. Try again, looking for the mistake:
</span><span>2x + 4 = 3(x – 2) + 1 => 2x + 4 = 3x - 6 + 1
4 = x - 5
9 = x
Check: Is 2(9) + 4 = 3(9-2) + 1 true? Is 18+4 = 22 true? YES.
The solution to #1 is x = 9 (answer).
Submit your other questions separately, please.
</span>
Answer:
1600
Step-by-step explanation:
Y=5a-3b
Y=5(12)-3(4)
Y=60-12
Y=48
You don't have a sign between b and c in the equation, so I cannot help you with the last operation
These array of numbers shown above are called matrices. These are rectangular arrays of number that are arranged in columns and rows. It is mostly useful in solving a system of linear equations. For example, you have these equations
x+3y=5
2x+y=1
x+y=10
In matrix form that would be
![\left[\begin{array}{ccc}1&3&5\\2&1&1\\1&1&10\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%265%5C%5C2%261%261%5C%5C1%261%2610%5Cend%7Barray%7D%5Cright%5D%20)
where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is
2.8y + 6 + 0.2y = 5y - 14
(Simplify like terms in first half of equation)
3y + 6 = 5y - 14
(Subtract both sides by 3y)
6 = 2y - 14
(Flip)
2y - 14 = 6
(Add both sides by 14)
2y = 20
(Divide both sides by 2)
y=10