Answer:
See below
Bold parts are important parts. They are the equations.
Marina had RM24,500 to invest.
If the amount of money in the 4% account was four times the amount of money in the 5.5% account.
" At the end of the year, she had made RM1,300 in interest. The annual yield on each of the three accounts was 4%, 5.5%, and 6%."
"If the amount of money in the 4% account was four times the amount of money in the 5.5% account,"
a = 4b
Down is the equations.
let a = amt in the 4% acct
let b = amt in the 5.5% acct
let c = amt in the 6%
"Marina had RM 24,500 to invest."
a + b + c = 24500
Replace a with 4b in both equations, simplify
b = $2000 in the 5.5% investment
a = $8000 in the 4% acct
<em><u>Hope this helps.</u></em>
Answer: ( 2 + 3 ) ( 8d )
Step-by-step explanation:
There are multiple possible answers and I'm not sure if you're missing part of the question.
Correct me if I am incorrect.
Answer:
1. x = -4y ---> y = (-1/4)x
slope = -1/4. y-intercept = (0,0)
2. y = -2x + 4
3. y = (1/3)x - 1
Step-by-step explanation:
1. Re-write your equation so that x is on the right and y is on the left:
x = -4y ---> y = (-1/4)x
slope = -1/4. y-intercept = (0,0)
2. y-intercept = (0,4) ----> P1
x-intercrpt = (2,0) ----> P2
slope m = (y2 - y1) / (x2 - x1)
= (0 - 4)/(2 - 0)
= -2
therefore, y - y1 = mx - x1 ---> y - 4 = -2x
or y = -2x + 4
3. y-intercept = (0,-1)
x-intercept = (3,0)
m = (0 - (-1)) / (3 -0) = 1/3
y - (-1) = (1/3)x - 0 ---> y = (1/3)x - 1
The blank box should be equal to 4