Honestly i agree with Nd12217 z is the answer to 136 x 150
Nevermind the answer is wrong
Answer: D. exponential growth
Step-by-step explanation:
Answer:

Step-by-step explanation:
We begin by solving for x in term of y



We can use the disk method to calculate the volume of rotation around the y axis

Where 
![V = \int\limits^5_4 {\pi \left(\frac{e^y}{3}\right)^2} \, dy\\V = \frac{\pi}{9}\int\limits^5_4 {e^{2y}} \, dy\\\\V = \frac{\pi}{9}\left[\frac{e^{2y}}{2}\right]^5_4\\V = \frac{\pi}{9}(e^{10}/2 - e^8/2) = \frac{\pi}{18}(e^{10} - e^8)\\ V = \frac{\pi}{18}19045.5 \approx 3324](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E5_4%20%7B%5Cpi%20%5Cleft%28%5Cfrac%7Be%5Ey%7D%7B3%7D%5Cright%29%5E2%7D%20%5C%2C%20dy%5C%5CV%20%3D%20%5Cfrac%7B%5Cpi%7D%7B9%7D%5Cint%5Climits%5E5_4%20%7Be%5E%7B2y%7D%7D%20%5C%2C%20dy%5C%5C%5C%5CV%20%3D%20%5Cfrac%7B%5Cpi%7D%7B9%7D%5Cleft%5B%5Cfrac%7Be%5E%7B2y%7D%7D%7B2%7D%5Cright%5D%5E5_4%5C%5CV%20%3D%20%5Cfrac%7B%5Cpi%7D%7B9%7D%28e%5E%7B10%7D%2F2%20-%20e%5E8%2F2%29%20%3D%20%5Cfrac%7B%5Cpi%7D%7B18%7D%28e%5E%7B10%7D%20-%20e%5E8%29%5C%5C%20V%20%3D%20%5Cfrac%7B%5Cpi%7D%7B18%7D19045.5%20%5Capprox%203324)
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I think the answer is <span>C) The number of circles on a page is 6 times the number of circles on the previous page.
</span>If we plugged in p = 1, then it leads to c(p) = 6
This is saying "on page 1 (p = 1), the number of circles on this page is 6"
<span>ie, "There are 6 circles on page 1"</span><span>
</span>
No because they can’t be expressed as ratios of the two integers