if indeed two functions are inverse of each other, then their composite will render a result of "x", namely, if g(x) is indeed an inverse of f(x), then
![\bf (g\circ f)(x)=x\implies g(~~f(x)~~)=x \\\\\\ \begin{cases} f(x) = 3x\\ g(x)=\cfrac{1}{3}x \end{cases}\qquad \qquad g(~~f(x)~~)=\cfrac{1}{3}[f(x)]\implies g(~~f(x)~~)=\cfrac{1}{3}(3x)](https://tex.z-dn.net/?f=%5Cbf%20%28g%5Ccirc%20f%29%28x%29%3Dx%5Cimplies%20g%28~~f%28x%29~~%29%3Dx%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20f%28x%29%20%3D%203x%5C%5C%20g%28x%29%3D%5Ccfrac%7B1%7D%7B3%7Dx%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%5Bf%28x%29%5D%5Cimplies%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%283x%29)
Answer:
35/100
Step-by-step explanation:
You have to find how many juniors there are, so if you add 13, 20, and 2 you get 35. For the denominator you have to find the total number of students, so just add all of the numbers together to get 100. So there is a 35/100 chance that a randomly selected student is a junior.
The difference of 7 and 7/8 and 3 1/4 can be restated as the difference between 63/8 and 13/4. This is just a change from mixed numbers to improper fractions.
We must now get a common denominator (the bottom part of a fraction). To get 8, we must multiply by 2 to the denominator of 13/4. Since we want this number to stay in the same value, we have to multiply the numerator by 2 as well (top part of the fraction). Therefore, we are getting the difference of 63/8 and 26/8. Doing this, we get (63-26)/8, so the answer is 37/8 = 4 5/8
Answer: y=5x/2 - 2.5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-2.5-2.5)/(0-2)
m=-5/(-2)
m=5/2
y=mx+b
y=5x/2 + b
-2.5=5(0)/2 + b
-2.5=0 + b
b=-2.5
y=5x/2 - 2.5
Answer:
D
Step-by-step explanation: