One of the ways to find the answer is to find how much 1 percent of 150 is. To do that we just have to divide 150 by 100:
150 / 100 = 1.5
Now we can divide 9 by 1.5 to know how much percent of 150 it is:
9 / 1.5 = 6
Let's check it:
150 * 6% = 150 * 6/100 = 15 * 6/10 = 3 * 6/2 = 18/2 = 9
It's correct then :)
The equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
<h3>What is linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have two equation of the line:
y = -x -3 and
5y + 5x = -15
From the equation 5y + 5x = -15:
Divide by 5 on the above equation:
y + x = -3
or
y = -x -3
The two equations y = -x -3 represents the same line.
Thus, the equations y = -x -3 and 5y + 5x = -15 represents the same line option 'the same line' is correct.
Learn more about the linear equation here:
brainly.com/question/11897796
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<1 = <2
vertical angles (congruent)
<3 = <2
corresponding angles (congruent)
so that: <1 = <2 = <3 = 112 degree
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.
5/7c ÷ 5/7 = c
13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5
Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70
Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.
So the answer is c = 1.3, or 1 and 3/10.
Hope this helps :)
