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lakkis [162]
3 years ago
9

In 2016, there were a total of 41 national battlefields and national memorials. The number of national memorials is three less t

han three times the number of national battlefields. How many of each park unit were there?
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
3 0

Answer: 11, 30

Step-by-step explanation:

Given

There were a total of 41 national battlefields and national memorials

Suppose there are x national battlefields

So, national memorials are 3x-3

The sum of the two must be 41

\Rightarrow x+3x-3=41\\\Rightarrow 4x=44\\\Rightarrow x=11

So, there are 11 national battlefields and 3\times 11-3=30 national memorials.

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2.4.5
worty [1.4K]

Answer:

150 miles

Step-by-step explanation:

let m represent miles

$70 + .70m = $40 + .90m

subtract 40 from each side

$30 + .70m = .90m

subtract .70m from each side

$30 = .20m

divide both sides by .20

150 = m

5 0
3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
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Mrs Tay had 425 cookies at first.
yKpoI14uk [10]

Answer:

425-65=360

360-65=295

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3 years ago
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Options 1 does not represent a function
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R(r1+r2)=r1r2<br> How do I solve for r
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The answer is r = 0,3

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