A plastic ball is filled with gel to make a stress ball. If the ball has a radius of 4 cm, how much
1 answer:
Answer:
267.947 cm^{3} of gel is required to fill the plastic ball.
Step-by-step explanation:
<em>The radius of the ball is given as 4 cm.</em>
<em>The gel is filled in the plastic ball, that means the gel occupies the volume of the radius.</em>
The volume of the sphere is given by the formula,
, the R is the radius of sphere.
Thus, the volume of gel required to fill the plastic ball to make it stress ball is
267.947 cm^{3} of gel.
You might be interested in
Female: Male:
60 35
96 109
26 31
n₁=no. of entries=3 n₂=no. of entries=3
s₁=sample standard s₂=sample standard
deviation=35.005 deviation=43.924
x₁=sample mean=60.666 x₂=sample mean=58.333
Here s and x are calculated from calculator.
Now,
for significance level
1-α=90%
1-α=0.9
α=0.1
α/2=0.05
As population variances are unknown for both Male and female so the best suitable formula is
(x₁ - x₂) ± tα/2,v₁ *
........1
where v(degree of fredom)=(s₁²/n₁+s₂²/n₂)² / ((s₁²/n₁)²/n₁-1)+(s₂²/n₂)²/n₂-1))
by putting values
v=3.81026
From Statistics table,
See the t table at α/2=0.05 and v=3.81026
use interpolation as v value is not in the table,
3.81026-3/4-3 = x-3.182/2.776-3.182
x= 2.853
by putting values in eq. 1 we get
(60.666-58.333) ± (2.853)*
2.333 ± 92.516 is the correct answer.
60 35
96 109
26 31
n₁=no. of entries=3 n₂=no. of entries=3
s₁=sample standard s₂=sample standard
deviation=35.005 deviation=43.924
x₁=sample mean=60.666 x₂=sample mean=58.333
Here s and x are calculated from calculator.
Now,
for significance level
1-α=90%
1-α=0.9
α=0.1
α/2=0.05
As population variances are unknown for both Male and female so the best suitable formula is
(x₁ - x₂) ± tα/2,v₁ *
........1
where v(degree of fredom)=(s₁²/n₁+s₂²/n₂)² / ((s₁²/n₁)²/n₁-1)+(s₂²/n₂)²/n₂-1))
by putting values
v=3.81026
From Statistics table,
See the t table at α/2=0.05 and v=3.81026
use interpolation as v value is not in the table,
3.81026-3/4-3 = x-3.182/2.776-3.182
x= 2.853
by putting values in eq. 1 we get
(60.666-58.333) ± (2.853)*
2.333 ± 92.516 is the correct answer.