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Mariana [72]
3 years ago
10

Given f(x)=17-x^2, what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics
1 answer:
Dmitry [639]3 years ago
7 0
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-----------------------------\\\\
f(x)=17-x^2\quad 
\begin{cases}
x_1=1\\
x_2=5
\end{cases}\implies \cfrac{f(5)-f(1)}{5-1}
\\\\\\
\cfrac{(17-5^2)-(17-1^2)}{5-1}\implies \cfrac{-8-16}{4}\implies \cfrac{-24}{4}\implies -6
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The graph is in the image

Midpoint =\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-3,\:9\right),\:\left(x_2,\:y_2\right)=\left(0,\:1\right)\\\\\left(\frac{0-3}{2},\:\frac{1+9}{2}\right)\\\\Add\:or\:subtract\:the\:numbers\\\\(\frac{-3}{2} , \frac{10}{2})  \\\\Simplify\\\\(-\frac{3}{2} , 5)\\

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