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2 years ago

If I average a speed of 60 miles per hour while driving, how many hours of driving time will it take me to reach Arizona?

Mathematics

2 answers:

Damm [24]2 years ago

6 0

The answer will be 1 1/2 hours

Mumz [18]2 years ago

3 0

Answer:

Well where do you start

Step-by-step explanation:

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Dovator [93]

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2 years ago

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Can someone tell me the procesa of a ratio 6th grade math plzzz

adoni [48]

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2 years ago

Which is a solution to the equation y=5x-6

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3 years ago

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If y=2x+10 and X= -2 then what is y

lara [203]

Y=2•(-2)+10
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2 years ago

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Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te

motikmotik

Given:

There are given that the cos function:

$cos210^{\circ}=-\frac{\sqrt{3}}{2}$

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

$cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}$

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

$\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}$

Then,

Put the value of cos210 degrees into the above function:

So,

$\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}$

Final answer:

Hence, the value of the cos(105) is shown below:

$cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}$

4 0

11 months ago