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2 years ago

If I average a speed of 60 miles per hour while driving, how many hours of driving time will it take me to reach Arizona?

Mathematics

2 answers:

Damm [24]2 years ago

6 0

The answer will be 1 1/2 hours

Mumz [18]2 years ago

3 0

Answer:

Well where do you start

Step-by-step explanation:

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Find the absolute value. 1 -31=___ -1 121=___ -1 -221=___

Veseljchak [2.6K]

I guess we will never know

5 0

2 years ago

Read 2 more answers

Factor 26r3s + 52r5 – 39r2s4.

algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> 13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)

To factor it all together;

13r²(2rs + 4r³ - 3s⁴)

Hope this helps!

7 0

2 years ago

A principal of $2600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 8 years?

almond37 [142]

To add 7.5% to a number you simply multiply the number by 1.075. To compound that amount year after year, you raise 1.075 to an exponent that corresponds to the number of years. 2600*(1.075^8)=4637.04234646

3 0

2 years ago

What is the answer so i can pass

Lelechka [254]

Answer:

8/100 is equivalent to 0.08

Step-by-step explanation:

The second digit place to the right of the decimal point is the hundredths place, so that is where the 8 belongs because it is 8/100 in fraction form.

Hope this helped :)

6 0

2 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: