Important: If you're discussing squares, please express "the square of x" as x^2 (not as x2).
Please note that your y=x^2+3 is NOT a line. I will assume (probably incorrectly!) that you meant y=2x+3. The slope of this line is 2, so the slope of any line perpendicular to y=2x+3 is -1/2.
Now use the point-slope equation of a straight line:
y-8 = (-1/2)(x-1) (answer)
Answer: y=2
Step-by-step explanation:
2x+3y=14 - 2x-y=6 = 4y=8
y=2
If you need x, just insert y into the equation and work out x from there
2x-2=6
2x=8
x=4
Answer:
X=-Y
Step-by-step explanation:
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Can you repost this with a picture please ?
