Please help! 10+ Mpoints
1 answer:
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Given:
The graph of a function .
To find:
The interval where .
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So, for
.
Now,
For , the graph of h(x) is above the x-axis. So,
.
For , the graph of h(x) is below the x-axis. So,
.
For , the graph of h(x) is below the x-axis. So,
.
Only for the interval , we get
.
Therefore, the correct option is A.
Answer: 70.909090909091%
Step-by-step explanation: Reading through the problem we have <em>78 is</em>, that's 78 equals, <em>what percent</em>, x/100, <em>of 110</em>, times 110.
It's important to understand that <em>percent</em> means over 100 so what percent would simply mean <em>x/100</em> or any variable but I will be using x.
So we have the equation
So cross canceling the 110 and 100 to 11 and 10, we have
Multiply both sides by 10 to get rid
of the fraction and we have 780 = 11x.
Now divide both sides by 11 and 70.909090909091 = x.
So, 78 is 70.909090909091% of 110.
Work is attached in the image provided.
Answer: Choice B
(-1,0), (-1,-2), (-3, -1), and (-3, -2)
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Explanation:
Let's focus on the point (2,0)
If we shift it 3 units to the left, then we subtract 3 from the x coordinate to get 2-3 = -1 as its new x coordinate. The y coordinate stays the same.
That means we move from (2,0) to (-1,0)
Based on this alone, choice B must be the answer as it's the only answer choice that mentions (-1,0).
If you shifted the other given points, you should find that they land on other coordinates mentioned in choice B.
