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3 years ago

Determine the positive real root of ln(x²) = 0.7

Mathematics

1 answer:

timama [110]3 years ago

5 0

Answer:

i have no clue.

Step-by-step explanation:

i am very tired while doing a math link so please, don't give me any trouble with this :)

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Bob is asked to construct a probability model for rolling a pair of fair dice. He lists the outcomes as 2, 3, 4, 5, 6, 7, 8,

vichka [17]

Answer and Step-by-step explanation:

For 2 dice, we have 36 possibles outcomes:

D₁ = {1,2,3,4,5,6}

D₂ = {1,2,3,4,5,6}

U = ({1,1};{1,2};{1,3};...;{2,1};{2,2};...;{6,6})

This way, it's 6 for D₁ and 6 for D₂, 6.6 = 36

The possible 3 that might appear when rolling a pair of dice would be

{1,2} and {2,1}, so, 2.

The probability of rolling 3 is 2/36 = 1/18

4 0

3 years ago

Suppose the same quantity is measured but with a more precise method giving an average and standard deviation of 15.0 ± 2.5. how

abruzzese [7]

To solve this, we use the z test.

The formula:

z = (x – u) / s

where x is sample value = 20, u is the mean = 15, and s is the standard deviation = 2.5

z = (20 – 15) / 2.5

z = 2

Since we are looking for values greater than 20, this is right tailed test. We use the standard distribution tables to find for P.

P = 0.0228

Therefore:

number of students = 100 * 0.0228 = 2.28

<span>2 to 3 students will get greater than 20 measurement</span>

7 0

2 years ago

Find all the square roots of x2 ≡ 53 (mod 77)

Nikolay [14]

Answer:

$x=\pm\sqrt{77n+53}$

Step-by-step explanation:

We have been given an equivalence equation $x^2\equiv 53\text{ (mod } 77)$ . We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

$x^2-53=77n$

Add 53 on both sides:

$x^2-53+53=77n+53$

$x^2=77n+53$

Take square root of both sides:

$x=\pm\sqrt{77n+53}$

Therefore, the square root for our given equation would be $x=\pm\sqrt{77n+53}$ .

3 0

3 years ago

Show (prove) in detail why (xyz)4 =x4 y4 z4 for any number x,y,z

Ganezh [65]

By using distributive property you can distribute (XYZ)4 and get a simplified answer of 4(x)+ 4(y) + 4 (z). The parenthesis show that 4(xyz) is not simplified and could also be written as 4(x)+ 4(y) + 4 (z).

7 0

3 years ago

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gi

inessss [21]

Answer:

$\frac{1429}{120}$ or $11\frac{109}{120}$

Step-by-step explanation:

Given:

A farmer has a basket of peaches. He gives ⅓ of the peaches to one person, ¼ to another, ⅕ to another, ⅛ to another, and then gives 7 peaches to a 5th person.

Remaining peaches = 4

We need to find the original number of peaches in the basket.

The farmer gives the total number of peaches = $\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7$

Let x be the former gives the total number of peaches

We multiply and divide by 120 in right side of the above equation because of 120 is divided by all given denominator and then simplify.

$x = \frac{120}{120}(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{8}+7)$

$x = \frac{1}{120}(\frac{120}{3}+\frac{120}{4}+\frac{120}{5}+\frac{120}{8}+7\times 120)$

$x = \frac{1}{120}(40+30+24+15+840)$

$x = \frac{1}{120}(949)$

$x = \frac{949}{120}$

We add the remaining peaches by given peaches for the original number of peaches in the basket.

Original number of peaches = $\frac{949}{120}+4$

Original number of peaches = $\frac{949+4\times 120}{120}$

Original number of peaches = $\frac{949+480}{120}$

Original number of peaches = $\frac{1429}{120}$

Original number of peaches = $11\frac{109}{120}$

Therefore the original number of peaches in the basket is $\frac{1429}{120}$ or $11\frac{109}{120}$

5 0

3 years ago