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Elena-2011 [213]
3 years ago
7

Chloe uses 80 candy wrappers to make a paper necklace she is making necklaces for herself and 9 friends how many candy wrappers

will Chloe need
Mathematics
1 answer:
Rasek [7]3 years ago
4 0
80x10=800 so thats the answer 10 because her friends and herself
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What is the constant of proportionality for the relationship between the length of the arc intercepted by a 80 degree angle and
Over [174]
So the length of the arc is given by: l = r*theta, here theta is the intercepted angle in unit radian

So, 80 degrees = 80/360 * 2pi = 4/9 * pi 

So l = r * (4/9 * pi), the constant ratio is 4/9 * pi
3 0
3 years ago
Plz answer my question it is urgent..!!
oee [108]

Answer:

In the step-by-step explanation!

Step-by-step explanation:

Not sure if it is too late but here:

1.)

\frac{1}{\alpha}+\frac{1}{\beta} \\\frac{\beta}{\alpha \beta } +\frac{\alpha}{\alpha \beta } \\\frac{\alpha +\beta }{\alpha \beta }

2.)

\frac{1 }{\alpha } *\frac{1}{\beta} = \frac{1*1}{\alpha*\beta} =\frac{1}{\alpha \beta}

3.)

\frac{1}{\alpha}-\frac{1}{\beta}\\ \frac{\beta}{\alpha \beta } -\frac{\alpha }{\alpha \beta } \\\frac{\beta -\alpha }{\alpha \beta }

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6 0
3 years ago
5 and 4 sevenths times negative 2 and 2 fifths
Dimas [21]

Answer:

3/2

Step-by-step explanation:

ugygv

6 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Write the equation of a line that passes through the points in the table.
lord [1]

Answer: do it have a answer choice if it do then its B,C and e

Step-by-step explanation:

6 0
3 years ago
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