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bagirrra123 [75]
3 years ago
11

Find all solutions of given equation 2cosx-1=0

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
2cosx=1
cosx=1/2
x=cos∧-1(1/2)
x=60degrees or 360-60=300degrees
depending on your limits if in radians pi/3 and 5pi/3
skad [1K]3 years ago
5 0
There are an infinite number of solutions, so I don't plan to list them all.
I'll list two of them, and then describe how to get all of the rest.

You said that      <u>2cos(x) - 1  =  0</u>

Add  1  to each side:     2cos(x) = 1

Divide each side by  2:    cos(x) = 1/2

The angles whose cosine is 1/2 are  60 degrees, 300 degrees,
and any multiple of 360 degrees added to either of those.
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Find the arc length of the partial circle.<br> Fither enter an exact answer in tom
natima [27]

Answer:

50.265(correct to 5 significant figure)/ 16π

Step-by-step explanation:

\pi({8}^{2} )( \frac{90degree}{360degree} )

= \pi(64)( \frac{1}{4}  )

=50.265(cor. to 5 sig.fig.)/ 16π

to find the arc length of a sector,we need to use πradius² times (sector's degree divided by 360degree).

3 0
3 years ago
Rafael ha comprado 185,8 kg. de manzanas y 300,2 kg. de naranjas. ¿Cuánto más pesan las naranjas que las manzanas? ¿Cuánto pesa
Anon25 [30]

Answer:

a.114.4kg

b. 486kg

Step-by-step explanation:

Firstly , we want to know the value with which the apples weigh more than the oranges

To calculate this, we simply subtract the weight of the oranges from that of the apple

Mathematically, that would be ;

300.2-185.8 = 114.4kg

The total weight of the things bought is calculated by adding both weights together

That would be 185.8 + 300.2 = 486 kg

8 0
3 years ago
Solve each inequality<br> 6&gt; -11 + a
borishaifa [10]

Answer:

6>-11+a

Add 11 on both sides

17>a

You have to have the variable on the left side. In order to do this, you have to also flip the sign.

a<17

Hope I helped!

3 0
4 years ago
What is the value of f(x) = 2 .2 Xfor f(-2)?
andreyandreev [35.5K]

Answer:

f(x)= 2.2x

Step-by-step explanation:

y=2.2x

Now; interchanging the role of X and y;

x=2.2y

x-2.2=y

then;

f(-2)=-2-4=-6

8 0
3 years ago
Solve the simultaneous equations <br> 3x + 4y = 5<br> 2x - 3y = 9
lisabon 2012 [21]

We label each equation

3x + 4y = 5 (1)

2x – 3y = 9 (2)

We now want to get rid of one of the variables (x or y). Lets get rid of x:

We need (1) and (2) to have the same number of x's so we multiple (1) by 2 and (2) by 3 so they both have 6 x's

6x + 8y = 10 (1)*2

6x - 9y = 27 (2)*3

Now to get rid of the x's we take one of the equations from the other. It is easier to do (2)*3 -(1)*2

 6x - 9y = 27 (2)*3

6x + 8y = 10 (1)*2

                                   

    -17y = 17  

If we devide this equation by -17 we get

y = -1

We can plug this value of y into (1) to get

3x -4 = 5

add 4 to both sides of the equation

3x = 9

Divide by 3

x = 3

Now to check put x and y into (2)

6 - (-3) = 9  

As this is true, we have the solution

x = 3, y = -1

8 0
4 years ago
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