Based on the given parameters, the value of the function h(-1) is -1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(-1)
This means that t = -1
So, we substitute t = -1 in the equation h(t) =-t^2 + t + 1
h(-1) =-(-1)^2 + (-1) + 1
Evaluate the exponent
h(-1) =-1 - 1 + 1
Evaluate the like terms
h(-1) = -1
Hence, the value of the function h(-1) is -1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(−1)
What is this a joke or what if so mark me brainlieast
The parabola's vertex would not be on the x-axis or y-axis and there would be no x-intercepts.
Answer:
Step-by-step explanation:
The given function is

The graph of this function is a parabola that opens downwards
The line
intersects this parabola, when

The teammate can spike the ball after 0.25 seconds or 0.5 seconds.
The two solutions are reasonable. When the volleyball is accelerating into the air, it passes a height of 8 after 0.25 seconds.
When the ball is dropping after it attains maximum height, it attains another height of 8 after 0.5 seconds again.
Answer:

Step-by-step explanation:
Area is the width (6/7 yd) multiplied by the height (1 yd).
6/7 x 1 = 6/7 