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zimovet [89]
3 years ago
7

Tell weather the ordered pair is a solution of the inequality.

Mathematics
1 answer:
horsena [70]3 years ago
3 0
<span>for a problem like this there is no one solution.  It is an inequality.  When you graph it you would start with the Y-intercept at (0,10) then you move down 2 on the y axis and move the the right 1 on the x axis as that is your slope. i really hope this helps you with this..wait is there a graph?? Now im confused O-o</span>
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2 years ago
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Find the probability
yawa3891 [41]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests which forms the Sample Space, n(S)=80

Let the Event (a friend of the bride) =A

Let the Event (a friend of the groom) =B

n(A) =59

n(B)=50

Friends of both bride and groom, n(A \cap B)=30

Therefore:

n(A \cup B)=n(A)+n(B)-n(A \cap B)\\n(A \cup B)=59+50-30\\n(A \cup B)=79

The number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(A \cup B) =\dfrac{n(A \cup B) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

4 0
3 years ago
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