1) 350 is 70% of what number?

kondaur [170]

1. We have to find the fifth term of f(n) = 7 - 4(n - 1).
That means x = 5. Substitute 5 into the equation for x.
f(n) = 7 - 4(5 - 1)
Subtract 5 - 1.
f(n) = 7 - 4(4)
Multiply 4 by 4.
f(n) = 7 - 16
Subtract 16 from 7.
f(n) = -9
The answer is D.

2. Since we have to find the first 4 terms, we have to solve for x = 1, 2, 3, & 4.
Multiply 1, 2, 3, and 4 by 6. We now have:
f(x) = 6 - 25 f(x) = 12 - 25 f(x) = 18 - 25 f(x) = 24 - 25
Subtract 25 from the first term: 6, 12, 18, and 24.
f(x) = -19 f(x) = -13 f(x) = -7 f(x) = -1
The answer is C.

3. Now, we have to find the first 3 terms of f(x) = 10(2)^x. So x is 1, 2, & 3.
Raise 2 to the powers of 1, 2, and 3. The equations are now:
f(x) = 10(2) f(x) = 10(4) f(x) = 10(8)
Then multiply 10 by the three terms: 2, 4, and 8.
f(x) = 20 f(x) = 40 f(x) = 80
The answer is A.

4. Find the 21st term of f(n) = 2 + 9(n - 1). Substitute 21 for n.
f(n) = 2 + 9(21 - 1)
Subtract 1 from 21.
f(n) = 2 + 9(20)
Multiply 9 by 20.
f(n) = 2 + 180
Add 2 to 180.
f(n) = 182
The answer is B.

5. Which sequence is described by f(n) = 2(3)^x-5.
This is the only one which I'm not sure how to solve. Since I don't know, I won't answer it because I don't want to give you the wrong answer to the question, sorry about that.

6. The ninth term in f(n) = 384(1/2)^n-1. Put 9 in for n & subtract 1 from 9.
f(n) = 384(1/2)^8
Raise 1/2 to the power of 8.
f(n) = 384(1/256)
Multiply 1/256 by 384.
f(n) = 384/256
Reduce the fraction & make it a mixed number.
f(n) = 1 1/2

Hope this helped!

5 0

3 years ago

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week

Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of individuals who work at home at least once per week = $\frac{41}{250}$ = 0.164

n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<em>99% confidence interval for p</em> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ , $0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ ]

= [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0

2 years ago

Which sentence best reflects a theme in, "The Piece of String" by Guy de Maupassant? (PLZZZ HELPPP)

Mariulka [41]

The answer is

(c) innocence is hard to prove without trust

Hope this helps :3

8 0

3 years ago

Read 2 more answers

Dade County Public Schools

deff fn [24]