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daser333 [38]
3 years ago
15

Bruh what is (-4×-6)-4²​

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

8

Step-by-step explanation:

the anwser is you use the formal

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scoray [572]
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3 years ago
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Graph the system of equations on graph paper.
masha68 [24]
<span>4. The x-coordinate of the solution is 9.
</span><span>5. The y-coordinate of the solution is −8 .
</span><span>6.The ordered pair that is the solution to the system lies in Quadrant IV .</span><span>

Proof:

Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{2 x + 3 y = -6 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:
{4 x + 3 y = 12 | (equation 1)
{0 x+(3 y)/2 = -12 | (equation 2)

Multiply equation 2 by 2/3:
{4 x + 3 y = 12 | (equation 1)
{0 x+y = -8 | (equation 2)

Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 36 | (equation 1)
{0 x+y = -8 | (equation 2)

Divide equation 1 by 4:
{x+0 y = 9 | (equation 1)
{0 x+y = -8 | (equation 2)

Collect results:

Answer:  {x = 9 , y = -8
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5 0
3 years ago
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8.260 in expanded word form
Fittoniya [83]
Eight and two hundred sixty one thousandths 
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Sophie has to choose seven different positive (non zero) whole numbers whose mean is 7.
Anna71 [15]

Answer:

The largest possible number is 28.

Step-by-step explanation:

Sophie has to choose seven different numbers whose mean is 7, this means that the sum of the numbers is 49. (since the mean is the sum of them all divided by 7 and if we want the mean to be 7, then the sum would need to be 49).

We are asked what is the largest possible number she could choose, so therefore, the other six numbers should be non-zero and the smallest ones so she would have to choose the numbers from 1 to 6 first.

Let's see how much they sum up: 1+2+3+4+5+6=21

So now, she needs one more number to sum up to 21 and that will give her 49 in total, this number is 28 (since 28 + 21 =49).

Thus, 28 is the largest number she could choose because if she chose any other greater number the mean would be bigger than 49.

4 0
3 years ago
Draw a square that is not a quadrilateral
nalin [4]
This is impossible by definition both need four sides so 
8 0
3 years ago
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